2023 Mathematics Competition

### Question 12

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### 3 comments

###### Emmanuel Obenwa

1 year ago

X-5 =4√x

Divide both sides by 4

X-5/4 =√x

Find the square of both sides

X^2-10X+25/16 = x

Multiply both sides by 16

X^2 - 10x+25 = 16x

X^2-26x+25 = 0

Solve the quadratic equation

(X-1)(x-25) = 0

So therefore

X= 1

X = 25

Square of x are

X = 1

X = 625

2+X are

2+1= 3

2 +25 = 27

2+x- x^2 will be

2+1 -1= 2

2+25-625= -598

###### Emmanuel Obenwa

1 year ago

X-5 =4√x

Divide both sides by 4

X-5/4 =√x

Find the square of both sides

X^2-10X+25/16 = x

Multiply both sides by 16

X^2 - 10x+25 = 16x

X^2-26x+25 = 0

Solve the quadratic equation

(X-1)(x-25) = 0

So therefore

X= 1

X = 25

Square of x are

X = 1

X = 625

2+X are

2+1= 3

2 +25 = 27

2+x- x^2 will be

2+1 -1= 2

2+1-625= -622